api to rpc use generic paradigm

This commit is contained in:
withchao 2023-02-09 15:38:50 +08:00
parent 2f7b65730a
commit eecf8bb8ae

View File

@ -4,8 +4,10 @@ import (
"Open_IM/pkg/api_struct"
"Open_IM/pkg/proto/group"
"context"
"errors"
"github.com/gin-gonic/gin"
"google.golang.org/grpc"
"reflect"
"testing"
)
@ -67,7 +69,8 @@ func KickGroupMember(c *gin.Context) {
// 默认 全部自动
NewRpc(NewApiBind[api_struct.KickGroupMemberReq, api_struct.KickGroupMemberResp](c), "", group.NewGroupClient, group.GroupClient.KickGroupMember).Execute()
// 可以自定义编辑请求和响应
NewRpc(NewApiBind[api_struct.KickGroupMemberReq, api_struct.KickGroupMemberResp](c), "", group.NewGroupClient, group.GroupClient.KickGroupMember).Before(func(apiReq *api_struct.KickGroupMemberReq, rpcReq *group.KickGroupMemberReq, bind func() error) error {
a := NewRpc(NewApiBind[api_struct.KickGroupMemberReq, api_struct.KickGroupMemberResp](c), "", group.NewGroupClient, group.GroupClient.KickGroupMember)
a.Before(func(apiReq *api_struct.KickGroupMemberReq, rpcReq *group.KickGroupMemberReq, bind func() error) error {
return bind()
}).After(func(rpcResp *group.KickGroupMemberResp, apiResp *api_struct.KickGroupMemberResp, bind func() error) error {
return bind()
@ -102,6 +105,22 @@ func (a *RpcRun[A, B, C, D, Z]) After(fn func(rpcResp D, apiResp *B, bind func()
return a
}
func (a *RpcRun[A, B, C, D, Z]) execute() (*B, error) {
userID, err := a.bind.OpUserID()
if err != nil {
return nil, err
}
opID := a.bind.OperationID()
var rpcReq C // C type => *Struct
rpcReq = reflect.New(reflect.TypeOf(rpcReq).Elem()).Interface().(C)
return nil, nil
}
func (a *RpcRun[A, B, C, D, Z]) Execute() {
}
func GetGrpcConn(name string) (*grpc.ClientConn, error) {
return nil, errors.New("todo")
}