fix: fill in the most recent sendTime for a gap message to prevent the client from repeatedly retrieving the same message due to sendTime being 0. (#3522)

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OpenIM-Gordon 2025-08-14 14:16:50 +08:00 committed by GitHub
parent 34971c8b96
commit 123abe9803
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2 changed files with 11 additions and 6 deletions

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@ -5,6 +5,11 @@ import (
"fmt"
"time"
"go.mongodb.org/mongo-driver/bson"
"go.mongodb.org/mongo-driver/bson/primitive"
"go.mongodb.org/mongo-driver/mongo"
"go.mongodb.org/mongo-driver/mongo/options"
"github.com/openimsdk/open-im-server/v3/pkg/common/storage/database"
"github.com/openimsdk/open-im-server/v3/pkg/common/storage/model"
"github.com/openimsdk/protocol/constant"
@ -14,10 +19,6 @@ import (
"github.com/openimsdk/tools/errs"
"github.com/openimsdk/tools/utils/datautil"
"github.com/openimsdk/tools/utils/jsonutil"
"go.mongodb.org/mongo-driver/bson"
"go.mongodb.org/mongo-driver/bson/primitive"
"go.mongodb.org/mongo-driver/mongo"
"go.mongodb.org/mongo-driver/mongo/options"
)
func NewMsgMongo(db *mongo.Database) (database.Msg, error) {
@ -1154,7 +1155,7 @@ func (m *MsgMgo) findBeforeDocSendTime(ctx context.Context, docID string, limit
if err != nil {
return 0, 0, err
}
for i := len(res) - 1; i > 0; i-- {
for i := len(res) - 1; i >= 0; i-- {
v := res[i]
if v.Msgs != nil && v.Msgs.Msg != nil && v.Msgs.Msg.SendTime > 0 {
return v.Msgs.Msg.Seq, v.Msgs.Msg.SendTime, nil
@ -1169,7 +1170,7 @@ func (m *MsgMgo) findBeforeSendTime(ctx context.Context, conversationID string,
limit := int64(-1)
if first {
first = false
limit = m.model.GetMsgIndex(seq)
limit = m.model.GetLimitForSingleDoc(seq)
}
docID := m.model.BuildDocIDByIndex(conversationID, i)
msgSeq, msgSendTime, err := m.findBeforeDocSendTime(ctx, docID, limit)

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@ -132,6 +132,10 @@ func (*MsgDocModel) GetMsgIndex(seq int64) int64 {
return (seq - 1) % singleGocMsgNum
}
func (*MsgDocModel) GetLimitForSingleDoc(seq int64) int64 {
return seq % singleGocMsgNum
}
func (*MsgDocModel) indexGen(conversationID string, seqSuffix int64) string {
return conversationID + ":" + strconv.FormatInt(seqSuffix, 10)
}