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fix: fill in the most recent sendTime for a gap message to prevent the client from repeatedly retrieving the same message due to sendTime being 0. (#3522)
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34971c8b96
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@ -5,6 +5,11 @@ import (
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"fmt"
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"time"
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"go.mongodb.org/mongo-driver/bson"
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"go.mongodb.org/mongo-driver/bson/primitive"
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"go.mongodb.org/mongo-driver/mongo"
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"go.mongodb.org/mongo-driver/mongo/options"
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"github.com/openimsdk/open-im-server/v3/pkg/common/storage/database"
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"github.com/openimsdk/open-im-server/v3/pkg/common/storage/model"
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"github.com/openimsdk/protocol/constant"
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@ -14,10 +19,6 @@ import (
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"github.com/openimsdk/tools/errs"
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"github.com/openimsdk/tools/utils/datautil"
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"github.com/openimsdk/tools/utils/jsonutil"
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"go.mongodb.org/mongo-driver/bson"
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"go.mongodb.org/mongo-driver/bson/primitive"
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"go.mongodb.org/mongo-driver/mongo"
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"go.mongodb.org/mongo-driver/mongo/options"
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)
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func NewMsgMongo(db *mongo.Database) (database.Msg, error) {
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@ -1154,7 +1155,7 @@ func (m *MsgMgo) findBeforeDocSendTime(ctx context.Context, docID string, limit
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if err != nil {
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return 0, 0, err
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}
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for i := len(res) - 1; i > 0; i-- {
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for i := len(res) - 1; i >= 0; i-- {
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v := res[i]
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if v.Msgs != nil && v.Msgs.Msg != nil && v.Msgs.Msg.SendTime > 0 {
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return v.Msgs.Msg.Seq, v.Msgs.Msg.SendTime, nil
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@ -1169,7 +1170,7 @@ func (m *MsgMgo) findBeforeSendTime(ctx context.Context, conversationID string,
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limit := int64(-1)
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if first {
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first = false
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limit = m.model.GetMsgIndex(seq)
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limit = m.model.GetLimitForSingleDoc(seq)
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}
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docID := m.model.BuildDocIDByIndex(conversationID, i)
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msgSeq, msgSendTime, err := m.findBeforeDocSendTime(ctx, docID, limit)
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@ -132,6 +132,10 @@ func (*MsgDocModel) GetMsgIndex(seq int64) int64 {
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return (seq - 1) % singleGocMsgNum
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}
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func (*MsgDocModel) GetLimitForSingleDoc(seq int64) int64 {
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return seq % singleGocMsgNum
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}
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func (*MsgDocModel) indexGen(conversationID string, seqSuffix int64) string {
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return conversationID + ":" + strconv.FormatInt(seqSuffix, 10)
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}
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