# by https://github.com/Cosmo-klara from __future__ import print_function import re import inflect import unicodedata # 后缀计量单位替换表 measurement_map = { "m": ["meter", "meters"], 'km': ["kilometer", "kilometers"], "km/h": ["kilometer per hour", "kilometers per hour"], "ft": ["feet", "feet"], "L": ["liter", "liters"], "tbsp": ["tablespoon", "tablespoons"], 'tsp': ["teaspoon", "teaspoons"], "h": ["hour", "hours"], "min": ["minute", "minutes"], "s": ["second", "seconds"], "°C": ["degree celsius", "degrees celsius"], "°F": ["degree fahrenheit", "degrees fahrenheit"] } # 识别 12,000 类型 _inflect = inflect.engine() # 转化数字序数词 _ordinal_number_re = re.compile(r'\b([0-9]+)\. ') # 我听说好像对于数字正则识别其实用 \d 会好一点 _comma_number_re = re.compile(r'([0-9][0-9\,]+[0-9])') # 时间识别 _time_re = re.compile(r'\b([01]?[0-9]|2[0-3]):([0-5][0-9])\b') # 后缀计量单位识别 _measurement_re = re.compile(r'\b([0-9]+(\.[0-9]+)?(m|km|km/h|ft|L|tbsp|tsp|h|min|s|°C|°F))\b') # 前后 £ 识别 ( 写了识别两边某一边的,但是不知道为什么失败了┭┮﹏┭┮ ) _pounds_re_start = re.compile(r'£([0-9\.\,]*[0-9]+)') _pounds_re_end = re.compile(r'([0-9\.\,]*[0-9]+)£') # 前后 $ 识别 _dollars_re_start = re.compile(r'\$([0-9\.\,]*[0-9]+)') _dollars_re_end = re.compile(r'([(0-9\.\,]*[0-9]+)\$') # 小数的识别 _decimal_number_re = re.compile(r'([0-9]+\.\s*[0-9]+)') # 分数识别 (形式 "3/4" ) _fraction_re = re.compile(r'([0-9]+/[0-9]+)') # 序数词识别 _ordinal_re = re.compile(r'[0-9]+(st|nd|rd|th)') # 数字处理 _number_re = re.compile(r'[0-9]+') def _convert_ordinal(m): """ 标准化序数词, 例如: 1. 2. 3. 4. 5. 6. Examples: input: "1. " output: "1st" 然后在后面的 _expand_ordinal, 将其转化为 first 这类的 """ ordinal = _inflect.ordinal(m.group(1)) return ordinal + ", " def _remove_commas(m): return m.group(1).replace(',', '') def _expand_time(m): """ 将 24 小时制的时间转换为 12 小时制的时间表示方式。 Examples: input: "13:00 / 4:00 / 13:30" output: "one o'clock p.m. / four o'clock am. / one thirty p.m." """ hours, minutes = map(int, m.group(1, 2)) period = 'a.m.' if hours < 12 else 'p.m.' if hours > 12: hours -= 12 hour_word = _inflect.number_to_words(hours) minute_word = _inflect.number_to_words(minutes) if minutes != 0 else '' if minutes == 0: return f"{hour_word} o'clock {period}" else: return f"{hour_word} {minute_word} {period}" def _expand_measurement(m): """ 处理一些常见的测量单位后缀, 目前支持: m, km, km/h, ft, L, tbsp, tsp, h, min, s, °C, °F 如果要拓展的话修改: _measurement_re 和 measurement_map """ sign = m.group(3) ptr = 1 # 想不到怎么方便的取数字,又懒得改正则,诶,1.2 反正也是复数读法,干脆直接去掉 "." num = int(m.group(1).replace(sign, '').replace(".",'')) decimal_part = m.group(2) # 上面判断的漏洞,比如 0.1 的情况,在这里排除了 if decimal_part == None and num == 1: ptr = 0 return m.group(1).replace(sign, " " + measurement_map[sign][ptr]) def _expand_pounds(m): """ 没找到特别规范的说明,和美元的处理一样,其实可以把两个合并在一起 """ match = m.group(1) parts = match.split('.') if len(parts) > 2: return match + ' pounds' # Unexpected format pounds = int(parts[0]) if parts[0] else 0 pence = int(parts[1].ljust(2, '0')) if len(parts) > 1 and parts[1] else 0 if pounds and pence: pound_unit = 'pound' if pounds == 1 else 'pounds' penny_unit = 'penny' if pence == 1 else 'pence' return '%s %s and %s %s' % (pounds, pound_unit, pence, penny_unit) elif pounds: pound_unit = 'pound' if pounds == 1 else 'pounds' return '%s %s' % (pounds, pound_unit) elif pence: penny_unit = 'penny' if pence == 1 else 'pence' return '%s %s' % (pence, penny_unit) else: return 'zero pounds' def _expand_dollars(m): """ change: 美分是 100 的限值, 应该要做补零的吧 Example: input: "32.3$ / $6.24" output: "thirty-two dollars and thirty cents" / "six dollars and twenty-four cents" """ match = m.group(1) parts = match.split('.') if len(parts) > 2: return match + ' dollars' # Unexpected format dollars = int(parts[0]) if parts[0] else 0 cents = int(parts[1].ljust(2, '0')) if len(parts) > 1 and parts[1] else 0 if dollars and cents: dollar_unit = 'dollar' if dollars == 1 else 'dollars' cent_unit = 'cent' if cents == 1 else 'cents' return '%s %s and %s %s' % (dollars, dollar_unit, cents, cent_unit) elif dollars: dollar_unit = 'dollar' if dollars == 1 else 'dollars' return '%s %s' % (dollars, dollar_unit) elif cents: cent_unit = 'cent' if cents == 1 else 'cents' return '%s %s' % (cents, cent_unit) else: return 'zero dollars' # 小数的处理 def _expand_decimal_number(m): """ Example: input: "13.234" output: "thirteen point two three four" """ match = m.group(1) parts = match.split('.') words = [] # 遍历字符串中的每个字符 for char in parts[1]: if char == '.': words.append("point") else: words.append(char) return parts[0] + " point " + " ".join(words) # 分数的处理 def _expend_fraction(m): """ 规则1: 分子使用基数词读法, 分母用序数词读法. 规则2: 如果分子大于 1, 在读分母的时候使用序数词复数读法. 规则3: 当分母为2的时候, 分母读做 half, 并且当分子大于 1 的时候, half 也要用复数读法, 读为 halves. Examples: | Written | Said | |:---:|:---:| | 1/3 | one third | | 3/4 | three fourths | | 5/6 | five sixths | | 1/2 | one half | | 3/2 | three halves | """ match = m.group(0) numerator, denominator = map(int, match.split('/')) numerator_part = _inflect.number_to_words(numerator) if denominator == 2: if numerator == 1: denominator_part = 'half' else: denominator_part = 'halves' elif denominator == 1: return f'{numerator_part}' else: denominator_part = _inflect.ordinal(_inflect.number_to_words(denominator)) if numerator > 1: denominator_part += 's' return f'{numerator_part} {denominator_part}' def _expand_ordinal(m): return _inflect.number_to_words(m.group(0)) def _expand_number(m): num = int(m.group(0)) if num > 1000 and num < 3000: if num == 2000: return 'two thousand' elif num > 2000 and num < 2010: return 'two thousand ' + _inflect.number_to_words(num % 100) elif num % 100 == 0: return _inflect.number_to_words(num // 100) + ' hundred' else: return _inflect.number_to_words(num, andword='', zero='oh', group=2).replace(', ', ' ') else: return _inflect.number_to_words(num, andword='') def normalize(text): """ !!! 所有的处理都需要正确的输入 !!! 可以添加新的处理,只需要添加正则表达式和对应的处理函数即可 """ text = re.sub(_ordinal_number_re, _convert_ordinal, text) text = re.sub(r'(?